## Wrecking Ball Hoist

In the below diagram, two cables merge together at point A to hoist up a 200 kg wrecking ball. What is the tension in the right cable?

##
__
__**Hint**

**Hint**

Free Body Diagram:

##
__
__**Hint 2**

**Hint 2**

First, evaluate the sum of forces about Point A. Keep in mind that
$$Force=mass\times acceleration$$
and
$$Tension_{left}=Tension_{right}$$
.

Free Body Diagram:

Keep in mind that
$$Force=mass\times acceleration$$
and
$$Tension_{left}=Tension_{right}$$
. Let's first evaluate the sum of forces about Point A:

$$$\sum F_y=0=2Tsin(60)-mg$$$

$$$mg=2Tsin(60)\rightarrow T=\frac{mg}{2sin(60)}$$$

$$$T=\frac{(200kg)(9.8m/s^2)}{2sin(60)}=\frac{1960}{1.732}N=1,132\:N$$$

Since the load is equally shared between the two cables, the right cable's tension is 1,132 N.

1,132 N