Heat Transfer

If the heat transfer coefficient is 70 W/[(m^2)(°C)], what is the heat transfer rate for 500°C hot air flowing across a 3 m^2 surface that is at 125°C?

Hint
$$$\dot{Q}=hA\Delta T$$$
where $$h$$ is the convection heat transfer coefficient of the fluid, $$A$$ is the convection surface area, $$\Delta T$$ is the change in temperature.
Hint 2
You don’t need to convert to Kelvin units.
Newton's Law of Cooling:
$$$\dot{Q}=hA\Delta T$$$
where $$h$$ is the convection heat transfer coefficient of the fluid, $$A$$ is the convection surface area, $$\Delta T$$ is the change in temperature.
$$$\dot{Q}=70\frac{W}{m^2C}(3m^2)(500^{\circ}C-125^{\circ}C)=78,750\:W$$$
78,750 W