Blinding (Sun)Light

Looking directly at the noonday sun on a clear day can blind you. What is the intensity of that blinding sunlight reaching your eyes in W/m^2? The sun has a luminosity of about 4 x 10^26 W and is 1.5 x 10^11 meters from us.

Expand Hint
Intensity:
$$$I=\frac{L}{4\pi R^2}$$$
where $$L$$ is the luminosity, and $$R$$ is the distance.
Hint 2
Don’t worry about converting any units.
Intensity:
$$$I=\frac{L}{4\pi R^2}$$$
where $$L$$ is the luminosity, and $$R$$ is the distance. Thus,
$$$I=\frac{4\cdot 10^{26}W}{4\pi (1.5\cdot 10^{11}m)^2}=\frac{10^{26}W}{2.25\pi \cdot 10^{22}m^2}$$$
$$$=\frac{10^{4}}{2.25\pi }W/m^2=1415\:\frac{W}{m^2}$$$
$$$1415\: W/m^2$$$
Time Analysis See how quickly you looked at the hint, solution, and answer. This is important for making sure you will finish the FE Exam in time.
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