PVT Behavior of an Ideal Gas
Consider a 5 L tank of nitrogen gas with a pressure of 1.0 atm. If the tank is compressed to a volume of 2 L, calculate the new pressure.
Expand Hint
$$$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$$$
where
$$P$$
is pressure,
$$V$$
is volume, and
$$T$$
is temperature.
Hint 2
Because temperate is not given in the problem statement, we can ignore that specific section of the equation. Therefore:
$$$P_1V_1=P_2V_2$$$
For an ideal gas:
$$$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$$$
where
$$P$$
is pressure,
$$V$$
is volume, and
$$T$$
is temperature.
Because temperature is not given in the problem statement, ignore that variable from the equation. Therefore:
$$$P_1V_1=P_2V_2$$$
$$$1atm\cdot 5L=P_2\cdot 2L$$$
$$$P_2=\frac{1atm(5L)}{2L}=2.5\:atm$$$
2.5 atm
Time Analysis
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Similar Problems from FE Section: PVT Behavior
183. Specific Weight
253. Ideal Gas
257. Nozzle Count
288. New Volume
513. Nozzles
555. Ideal Volume