## Sphere’s Equation

What is the equation for a sphere with a diameter of 6, and a center at (-1, 0, 1)?

##
__
__**Hint**

**Hint**

The standard form of a sphere equation is:

$$$(x-h)^{2}+(y-k)^{2}+(z-m)^{2}=r^{2}$$$

##
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__**Hint 2**

**Hint 2**

In the standard form of a sphere equation, its center is at
$$(h, k, m)$$
and
$$r$$
is the radius.

The standard form of a sphere equation is:

$$$(x-h)^{2}+(y-k)^{2}+(z-m)^{2}=r^{2}$$$

where the sphere’s center is at
$$(h, k, m)$$
and
$$r$$
is the radius.

Thus,

$$$(x-(-1))^{2}+(y-0)^{2}+(z-1)^{2}=(\frac{6}{2})^{2}$$$

$$$(x+1)^{2}+(y-0)^{2}+(z-1)^{2}=(3)^{2}=9$$$

$$$(x+1)^{2}+(y-0)^{2}+(z-1)^{2}=9$$$