Sphere’s Equation
What is the equation for a sphere with a diameter of 6, and a center at (-1, 0, 1)?
Expand Hint
The standard form of a sphere equation is:
$$$(x-h)^{2}+(y-k)^{2}+(z-m)^{2}=r^{2}$$$
Hint 2
In the standard form of a sphere equation, its center is at
$$(h, k, m)$$
and
$$r$$
is the radius.
The standard form of a sphere equation is:
$$$(x-h)^{2}+(y-k)^{2}+(z-m)^{2}=r^{2}$$$
where the sphere’s center is at
$$(h, k, m)$$
and
$$r$$
is the radius.
Thus,
$$$(x-(-1))^{2}+(y-0)^{2}+(z-1)^{2}=(\frac{6}{2})^{2}$$$
$$$(x+1)^{2}+(y-0)^{2}+(z-1)^{2}=(3)^{2}=9$$$
$$$(x+1)^{2}+(y-0)^{2}+(z-1)^{2}=9$$$
Time Analysis
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Similar Problems from FE Section: Quadric Surface (SPHERE)
103. Sphere Equation
433. Distance in 3D Space
437. Distance in 2D Space