## Specific Weight

If the universal gas constant, R, is 8.314 kPa(m^3)/(kmol∙K), determine the specific gas constant for a gas that has a molecular weight of 40.

Hint
$$R_{i}=\frac{\bar{R}}{(mol.wt_i)}$$$where $$\bar R$$ is the universal gas constant. Hint 2 The units for a specific gas constant are in $$\frac{J}{kg\cdot K}$$ . R is specific to each gas, but can be calculated from: $$R_{i}=\frac{\bar{R}}{(mol.wt_i)}$$$
where $$\bar R$$ is the universal gas constant.
$$R_{specific}=\frac{8.314kPa(m^3)}{40(kmol\cdot K)}$$$$$R_{specific}=0.208\:\frac{kJ}{kg\cdot K}$$$
0.208 $$kJ/kg\cdot K$$