## Specific Weight

If the universal gas constant, R, is 8.314 kPa(m^3)/(kmolâˆ™K), determine the specific gas constant for a gas that has a molecular weight of 40.

##
__
__**Hint**

**Hint**

$$$R_{i}=\frac{\bar{R}}{(mol.wt_i)}$$$

where
$$\bar R$$
is the universal gas constant.

##
__
__**Hint 2**

**Hint 2**

The units for a specific gas constant are in
$$\frac{J}{kg\cdot K}$$
.

R is specific to each gas, but can be calculated from:

$$$R_{i}=\frac{\bar{R}}{(mol.wt_i)}$$$

where
$$\bar R$$
is the universal gas constant.

$$$R_{specific}=\frac{8.314kPa(m^3)}{40(kmol\cdot K)}$$$

$$$R_{specific}=0.208\:\frac{kJ}{kg\cdot K}$$$

0.208
$$kJ/kg\cdot K$$