## Lever Arm

In the lever arm below, calculate the moment force (F) causes on Point A.

##
__
__**Hint**

**Hint**

The diagonal force applied at the end of the lever arm can be broken down into a
$$F_x$$
component.

$$$F_x=F\cdot cos(\theta)$$$

##
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__**Hint 2**

**Hint 2**

The diagonal force applied at the end of the lever arm can be broken down into a
$$F_y$$
component.

$$$F_y=F\cdot sin(\theta)$$$

The diagonal force applied at the end of the lever arm can be broken down into
$$F_x$$
and
$$F_y$$
components.

$$$F_x=F\cdot cos(\theta)=700\cdot cos(30)=606.22\:N$$$

$$$F_y=F\cdot sin(\theta)=700\cdot sin(30)=350\:N$$$

A system of two forces that are equal in magnitude, opposite in direction, and parallel to each other is called a couple. A moment (M) is defined as the cross product of the radius vector (r) and the force (f) from a point to the force's line of action.

$$$M=r \times F$$$

$$$M_z=xF_y-yF_x$$$

Thus, the moment about Point A:

$$$M_A=(6m)(350N)-(1m)(606.22N)=2100-606.22=1494\:N\cdot m$$$

$$$1494\:N\cdot m$$$