Nozzle Count

In an experiment, a machine uses several nozzles that can only individually produce 40 kg/s of an ideal gas mixture with an average molecular weight of 20. How many nozzles are required to produce a volumetric flow rate of 25 m^3/s at 320 K and 420 kPa? Note the universal gas constant is 8.314 kPa∙m^3/(kmol∙K).

Hint
Ideal gas formula:
$$$Pv=RT$$$
where $$P$$ is pressure, $$v$$ is the specific volume, $$R$$ is the gas constant, and $$T$$ is the absolute temperature.
Hint 2
$$$\dot{m}=\rho \times \dot{V}$$$
where $$\dot{m}$$ is the mass flow rate, $$\rho$$ is density of the fluid, and $$\dot V$$ is volumetric flow rate.
Ideal gas formula:
$$$Pv=RT$$$
where $$P$$ is pressure, $$v$$ is the specific volume, $$R$$ is the gas constant, and $$T$$ is the absolute temperature. Since $$R=\bar{R}/M$$ , where $$\bar{R}$$ is the universal gas constant and $$M$$ is the molecular weight:
$$$v=\frac{\bar{R}T}{MP}$$$
To solve for mass flow rate of the entire machine:
$$$\dot{m}=\rho \times \dot{V}$$$
where $$\rho$$ is density of the fluid, and $$\dot V$$ is volumetric flow rate. Since the specific volume ( $$v$$ ) is the reciprocal of the fluid’s density ( $$\rho$$ ):
$$$\dot{m}=\frac{\dot{V}}{v}=\frac{\dot{V}MP}{\bar{R}T}$$$
$$$=\frac{(20kg/kmol)(420kPa)(25m^3/s)}{(320K)(8.314kPa\cdot m^3/(kmol\cdot K))}=\frac{210,000}{2,660.5}=78.9\:kg/s$$$
Since each nozzle produces 40 kg/s:
$$$\frac{78.9kg/s}{40kg/s}=1.9\:nozzles$$$
The machine will need 2 nozzles.
2