## Ellipse

What is the eccentricity of the conic section represented by the below equation?

##
__
__**Hint**

**Hint**

The equation for an ellipse has the below format:

$$$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$$$

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__**Hint 2**

**Hint 2**

Eccentricity:

$$$e=\sqrt{1-(b^2/a^2)}$$$

A conic section is a curve obtained from the intersection of a cone’s surface and a flat plane. The eccentricity,
$$e$$
, of a conic section indicates how close its shape is a circle. As eccentricity grows larger, the less the shape resembles a circle. The problem’s equation is an ellipse because it has the below format:

$$$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$$$

The eccentricity,
$$e$$
, of a conic section indicates how close its shape is a circle. To solve for eccentricity:

$$$e=\sqrt{1-(b^2/a^2)}$$$

Thus,

$$$e=\sqrt{1-(9/16)}=\sqrt{1-0.5625}=\sqrt{0.4375}=0.66$$$

0.66