## Rivet Strength

Consider a certain material with a shear strength of 1,000 psi is machined into a rivet with a 0.5 inch diameter. What is the max shear force (lb) the rivet can handle before failure?

Hint
Failure by Pure Shear:
$$\tau=\frac{F}{A}$$$where $$F$$ is the shear load and $$A$$ is the cross sectional area of the bolt or rivet. Hint 2 Area of a circle: $$A=\frac{\pi}{4}d^2$$$
where $$d$$ is the diameter.
Failure by Pure Shear:
$$\tau=\frac{F}{A}$$$where $$F$$ is the shear load and $$A$$ is the cross sectional area of the bolt or rivet. Area of a circle: $$A=\frac{\pi}{4}d^2$$$
where $$d$$ is the diameter.

Combining the two equations to solve for the max shear force:
$$A=\frac{F}{\tau}=\frac{\pi}{4}d^2$$$$$F=\tau\frac{\pi}{4}d^2=(1,000\frac{lb}{in^2})\frac{\pi}{4}(0.5in)^2=196\:lb$$$
196 lb