Power Screw Load

#520 / Mechanical Engineering Easy

If a 90% efficient square thread power screw has a lead of 0.05 m, what is the max load (kN) can it raise with a 100 N∙m torque input?

Expand Hint
The power screw’s efficiency is:
$$$\eta=\frac{Fl}{2\pi T}$$$
where $$F$$ is the load, $$l$$ is the lead, and $$T$$ is the torque.
Hint 2
Solve for $$F$$ .
The power screw’s efficiency is:
$$$\eta=\frac{Fl}{2\pi T}$$$
where $$F$$ is the load, $$l$$ is the lead, and $$T$$ is the torque.

Solving for load:
$$$0.9=\frac{F(0.05m)}{2\pi (100 N\cdot m)}$$$
$$$F=\frac{(0.9)2\pi (100 N\cdot m)}{0.05m}=\frac{565.2N}{0.05}=11,304N=11.3\:kN$$$
11.3 kN


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