## Degrees of Freedom

Using the Gibbs Phase rule, how many degrees of freedom exist at the liquid state of gold?

##
__
__**Expand Hint**

**Expand Hint**

Gibbs Phase Rule (non-reacting systems):

$$$P+F=C+2$$$

where
$$P$$
is the number of phases making up a system,
$$F$$
is the degrees of freedom, and
$$C$$
is the number of components in a system.

##
__
__**Hint 2**

**Hint 2**

Since gold is the only component in the system,
$$C=1$$
.

Gibbs Phase Rule (non-reacting systems):

$$$P+F=C+2$$$

where
$$P$$
is the number of phases making up a system,
$$F$$
is the degrees of freedom, and
$$C$$
is the number of components in a system.

Based on the givens from the problem statement:

$$P=1$$
(gold only exists in the liquid state)

$$C=1$$
(gold is the only substance in the system)

Solving for degrees of freedom,
$$F$$
:

$$$F=C+2-P=1+2-1=2$$$

2

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