## Degrees of Freedom

Using the Gibbs Phase rule, how many degrees of freedom exist at the liquid state of gold?

Expand Hint
Gibbs Phase Rule (non-reacting systems):
$$P+F=C+2$$$where $$P$$ is the number of phases making up a system, $$F$$ is the degrees of freedom, and $$C$$ is the number of components in a system. Hint 2 Since gold is the only component in the system, $$C=1$$ . Gibbs Phase Rule (non-reacting systems): $$P+F=C+2$$$
where $$P$$ is the number of phases making up a system, $$F$$ is the degrees of freedom, and $$C$$ is the number of components in a system.

Based on the givens from the problem statement:
$$P=1$$ (gold only exists in the liquid state)
$$C=1$$ (gold is the only substance in the system)

Solving for degrees of freedom, $$F$$ :
$$F=C+2-P=1+2-1=2$$\$
2
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