Degrees of Freedom

Using the Gibbs Phase rule, how many degrees of freedom exist at the liquid state of gold?

Expand Hint
Gibbs Phase Rule (non-reacting systems):
$$$P+F=C+2$$$
where $$P$$ is the number of phases making up a system, $$F$$ is the degrees of freedom, and $$C$$ is the number of components in a system.
Hint 2
Since gold is the only component in the system, $$C=1$$ .
Gibbs Phase Rule (non-reacting systems):
$$$P+F=C+2$$$
where $$P$$ is the number of phases making up a system, $$F$$ is the degrees of freedom, and $$C$$ is the number of components in a system.

Based on the givens from the problem statement:
$$P=1$$ (gold only exists in the liquid state)
$$C=1$$ (gold is the only substance in the system)

Solving for degrees of freedom, $$F$$ :
$$$F=C+2-P=1+2-1=2$$$
2
Similar Problems from FE Sub Section: Gibbs Phase Rule
329. Gibbs Phase Rule

Similar Problems from FE Section: Phase Relations
329. Gibbs Phase Rule