Degrees of Freedom
Using the Gibbs Phase rule, how many degrees of freedom exist at the liquid state of gold?
Expand Hint
Gibbs Phase Rule (non-reacting systems):
$$$P+F=C+2$$$
where
$$P$$
is the number of phases making up a system,
$$F$$
is the degrees of freedom, and
$$C$$
is the number of components in a system.
Hint 2
Since gold is the only component in the system,
$$C=1$$
.
Gibbs Phase Rule (non-reacting systems):
$$$P+F=C+2$$$
where
$$P$$
is the number of phases making up a system,
$$F$$
is the degrees of freedom, and
$$C$$
is the number of components in a system.
Based on the givens from the problem statement:
$$P=1$$
(gold only exists in the liquid state)
$$C=1$$
(gold is the only substance in the system)
Solving for degrees of freedom,
$$F$$
:
$$$F=C+2-P=1+2-1=2$$$
2
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