## Thermal Deformation

A 5 meter long aluminum I-beam is heated from 50°C to 60°C. If the coefficient for thermal expansion of aluminum is 0.000012 m/m°C, calculate the thermal deformation due to temperature change.

##
__
__**Hint**

**Hint**

$$$\delta_t=\alpha L(T-T_0)$$$

where
$$\delta_t$$
is the deformation caused by a temp change,
$$\alpha$$
is the temp coefficient of expansion,
$$L$$
is the member length,
$$T$$
is the final temp, and
$$T_0$$
is the initial temp.

##
__
__**Hint 2**

**Hint 2**

Solve for
$$\delta_t$$
:

$$$\delta_t=0.000012\frac{m}{m^{\circ}C}\cdot 5m\cdot (60^{\circ}C-50^{\circ}C)$$$

The equation for thermal deformation is:

$$$\delta_t=\alpha L(T-T_0)$$$

where
$$\delta_t$$
is the deformation caused by a temp change,
$$\alpha$$
is the temp coefficient of expansion,
$$L$$
is the member length,
$$T$$
is the final temp, and
$$T_0$$
is the initial temp.

$$$\delta_t=0.000012\frac{m}{m^{\circ}C}\cdot 5m\cdot (60^{\circ}C-50^{\circ}C)=0.0006\:m$$$

0.0006 m