Thermal Deformation

A 5 meter long aluminum I-beam is heated from 50°C to 60°C. If the coefficient for thermal expansion of aluminum is 0.000012 m/m°C, calculate the thermal deformation due to temperature change.

Hint
$$\delta_t=\alpha L(T-T_0)$$$where $$\delta_t$$ is the deformation caused by a temp change, $$\alpha$$ is the temp coefficient of expansion, $$L$$ is the member length, $$T$$ is the final temp, and $$T_0$$ is the initial temp. Hint 2 Solve for $$\delta_t$$ : $$\delta_t=0.000012\frac{m}{m^{\circ}C}\cdot 5m\cdot (60^{\circ}C-50^{\circ}C)$$$
The equation for thermal deformation is:
$$\delta_t=\alpha L(T-T_0)$$$where $$\delta_t$$ is the deformation caused by a temp change, $$\alpha$$ is the temp coefficient of expansion, $$L$$ is the member length, $$T$$ is the final temp, and $$T_0$$ is the initial temp. $$\delta_t=0.000012\frac{m}{m^{\circ}C}\cdot 5m\cdot (60^{\circ}C-50^{\circ}C)=0.0006\:m$$$
0.0006 m