Thermal Deformation
A 5 meter long aluminum I-beam is heated from 50°C to 60°C. If the coefficient for thermal expansion of aluminum is 0.000012 m/m°C, calculate the thermal deformation due to temperature change.
Expand Hint
$$$\delta_t=\alpha L(T-T_0)$$$
where
$$\delta_t$$
is the deformation caused by a temp change,
$$\alpha$$
is the temp coefficient of expansion,
$$L$$
is the member length,
$$T$$
is the final temp, and
$$T_0$$
is the initial temp.
Hint 2
Solve for
$$\delta_t$$
:
$$$\delta_t=0.000012\frac{m}{m^{\circ}C}\cdot 5m\cdot (60^{\circ}C-50^{\circ}C)$$$
The equation for thermal deformation is:
$$$\delta_t=\alpha L(T-T_0)$$$
where
$$\delta_t$$
is the deformation caused by a temp change,
$$\alpha$$
is the temp coefficient of expansion,
$$L$$
is the member length,
$$T$$
is the final temp, and
$$T_0$$
is the initial temp.
$$$\delta_t=0.000012\frac{m}{m^{\circ}C}\cdot 5m\cdot (60^{\circ}C-50^{\circ}C)=0.0006\:m$$$
0.0006 m
Time Analysis
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Similar Problems from FE Section: Thermal Deformations
231. Subway Hand Rail
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