## Heat Transferring

If the heat transfer coefficient is 80 W/[(m^2)(°C)], what is the heat transfer rate for 400°C hot air flowing across a 4 m^2 surface that is at 100°C?

Hint
$$\dot{Q}=hA\Delta T$$$where $$h$$ is the convection heat transfer coefficient of the fluid, $$A$$ is the convection surface area, $$\Delta T$$ is the change in temperature. Hint 2 You don’t need to convert to Kelvin units. Newton's Law of Cooling: $$\dot{Q}=hA\Delta T$$$
where $$h$$ is the convection heat transfer coefficient of the fluid, $$A$$ is the convection surface area, $$\Delta T$$ is the change in temperature.
$$\dot{Q}=80\frac{W}{m^2C}(4m^2)(400^{\circ}C-100^{\circ}C)=96,000\:W$$\$
96,000 W