Heat Transfer
If the heat-transfer coefficient is 70 W/[(m^2)(°C)], what is the heat transfer rate for 500°C hot air flowing across a 3 m^2 surface that is at 125°C?
Expand Hint
$$$\dot{Q}=hA\Delta T$$$
where
$$h$$
is the convection heat transfer coefficient of the fluid,
$$A$$
is the convection surface area,
$$\Delta T$$
is the change in temperature.
Hint 2
No need to convert to Kelvin units.
Newton's Law of Cooling:
$$$\dot{Q}=hA\Delta T$$$
where
$$h$$
is the convection heat transfer coefficient of the fluid,
$$A$$
is the convection surface area,
$$\Delta T$$
is the change in temperature.
$$$\dot{Q}=70\frac{W}{m^2C}(3m^2)(500^{\circ}C-125^{\circ}C)=78,750\:W$$$
78,750 W
Time Analysis
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