Roots

Find a negative root that satisfies the following equation:

Hint
Quadratic Equation Formula:
$$$x_1,x_2=\frac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2a}$$$
Hint 2
Quadratic Equation Form:
$$$ax^2+bx+c=0$$$
Quadratic Equation Formula:
$$$x_1,x_2=\frac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2a}$$$
Quadratic Equation Form:
$$$ax^2+bx+c=0$$$
Thus,
$$$x_1,x_2=\frac{-50\pm \sqrt{50^{2}-4\cdot 25\cdot (-2)}}{2(25)}$$$
$$$x_1,x_2=\frac{-50\pm \sqrt{2,500-(-200)}}{50}$$$
$$$x_1,x_2=\frac{(-50\pm 51.96)}{50}$$$
Next,
$$$x_1=\frac{(-50+51.96)}{50}=\frac{1.96}{50}=0.0392$$$
$$$x_2=\frac{(-50-51.96)}{50}=\frac{101.96}{50}=-2.04$$$
Because $$x_2$$ is the only negative root, -2.04 is the answer.
-2.04