Parallel Plates
Find the max potential difference (kV) between two conducting parallel plates separated by 0.100 cm of nitrogen if the nitrogen’s max sustainable electric field strength is 5x10^6 V/m.
Expand Hint
The potential difference,
$$V$$
, between two points is the work per unit charge required to move the charge between the points. This is called the electric field.
Hint 2
The electric field produced by two parallel plates is:
$$$E=\frac{V}{d}$$$
where
$$V$$
is the voltage potential difference, and
$$d$$
is the separated distance.
The potential difference,
$$V$$
, between two points is the work per unit charge required to move the charge between the points. This is called the electric field. The electric field produced by two parallel plates is:
$$$E=\frac{V}{d}$$$
where
$$V$$
is the voltage potential difference, and
$$d$$
is the separated distance.
$$$5\cdot 10^6V/m=\frac{V_{potential}}{0.001m}$$$
$$$V_{potential}=5\cdot 10^6\frac{V}{m} \times 0.001m=5,000V=5\:kV$$$
5 kV
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