## Resistors in Parallel

A circuit contains four resistors in parallel: 2 Ω, 4Ω, 4Ω, and 8Ω. Determine the total resistance.

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__**Hint**

**Hint**

For resistors connected in parallel, the voltage drop across each resistors is equivalent.

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__**Hint 2**

**Hint 2**

$$$R_{parallel}=\frac{1}{(1/R_1)+(1/R_2)+...+(1/R_n)}$$$

For resistors connected in parallel, the voltage drop across each resistors is equivalent. Therefore, the resistance of
$$n$$
resistors in parallel is:

$$$R_{parallel}=\frac{1}{(1/R_1)+(1/R_2)+...+(1/R_n)}$$$

$$$R_{parallel}=\frac{1}{(1/2)+(1/4)+(1/4)+(1/8)}$$$

$$$R_{parallel}=\frac{1}{(4/8)+(2/8)+(2/8)+(1/8)}$$$

$$$R_{parallel}=\frac{1}{(9/8)}=\frac{8}{9}\: \Omega$$$

8/9 Ω