## Resistors in Parallel

A circuit contains four resistors in parallel: 2 Ω, 4Ω, 4Ω, and 8Ω. Determine the total resistance.

Hint
For resistors connected in parallel, the voltage drop across each resistors is equivalent.
Hint 2
$$R_{parallel}=\frac{1}{(1/R_1)+(1/R_2)+...+(1/R_n)}$$$For resistors connected in parallel, the voltage drop across each resistors is equivalent. Therefore, the resistance of $$n$$ resistors in parallel is: $$R_{parallel}=\frac{1}{(1/R_1)+(1/R_2)+...+(1/R_n)}$$$
$$R_{parallel}=\frac{1}{(1/2)+(1/4)+(1/4)+(1/8)}$$$$$R_{parallel}=\frac{1}{(4/8)+(2/8)+(2/8)+(1/8)}$$$
$$R_{parallel}=\frac{1}{(9/8)}=\frac{8}{9}\: \Omega$$\$
8/9 Ω