Strain

In the figure below, a 3 cm diameter by 1 m long titanium rod is placed under tension by a 45 N force. If it elongates by 0.05 cm, what is the strain in the rod?

Hint
Strain is the change in length per unit length.
Hint 2
$$$\varepsilon=\frac{\Delta L}{L_o} $$$
where $$\varepsilon$$ is the engineering strain, $$\Delta L$$ is the change in length, and $$L_o$$ is the original length.
Strain is the change in length per unit length.
$$$\varepsilon=\frac{\Delta L}{L_o} $$$
where $$\varepsilon$$ is the engineering strain, $$\Delta L$$ is the change in length, and $$L_o$$ is the original length. Therefore:
$$$\varepsilon=\frac{0.05cm}{100m}=0.0005$$$
0.0005