## Strain

In the figure below, a 3 cm diameter by 1 m long titanium rod is placed under tension by a 45 N force. If it elongates by 0.05 cm, what is the strain in the rod?

##
__
__**Hint**

**Hint**

Strain is the change in length per unit length.

##
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__**Hint 2**

**Hint 2**

$$$\varepsilon=\frac{\Delta L}{L_o} $$$

where
$$\varepsilon$$
is the engineering strain,
$$\Delta L$$
is the change in length, and
$$L_o$$
is the original length.

Strain is the change in length per unit length.

$$$\varepsilon=\frac{\Delta L}{L_o} $$$

where
$$\varepsilon$$
is the engineering strain,
$$\Delta L$$
is the change in length, and
$$L_o$$
is the original length. Therefore:

$$$\varepsilon=\frac{0.05cm}{100m}=0.0005$$$

0.0005