Strain

#309 / Mechanics of Materials Easy

In the figure shown, a 3 cm diameter by 1 m long titanium rod is placed under tension by a 45 N force. If it elongates by 0.05 cm, what is the strain in the rod?

Expand Hint
Strain is the change in length per unit length.
Hint 2
$$$\varepsilon=\frac{\Delta L}{L_o} $$$
where $$\varepsilon$$ is the engineering strain, $$\Delta L$$ is the change in length, and $$L_o$$ is the original length.
Strain is the change in length per unit length.
$$$\varepsilon=\frac{\Delta L}{L_o} $$$
where $$\varepsilon$$ is the engineering strain, $$\Delta L$$ is the change in length, and $$L_o$$ is the original length. Therefore:
$$$\varepsilon=\frac{0.05cm}{100cm}=0.0005$$$
0.0005


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