Total Resistance

A circuit contains four resistors in parallel: 3 Ω, 6Ω, 9Ω, and 9Ω. Determine the total resistance.

Expand Hint
For resistors connected in parallel, the voltage drop across each resistors is equivalent.
Hint 2
$$$R_{parallel}=\frac{1}{(1/R_1)+(1/R_2)+...+(1/R_n)}$$$
For resistors connected in parallel, the voltage drop across each resistors is equivalent. Therefore, the resistance of $$n$$ resistors in parallel is:
$$$R_{parallel}=\frac{1}{(1/R_1)+(1/R_2)+...+(1/R_n)}$$$
$$$R_{parallel}=\frac{1}{(1/3)+(1/6)+(1/9)+(1/9)}$$$
$$$R_{parallel}=\frac{1}{(12/36)+(6/36)+(4/36)+(4/36)}$$$
$$$R_{parallel}=\frac{1}{(26/36)}=\frac{36}{26}=1.38\: \Omega$$$
1.38 Ω