Initial Velocity
A motorcycle is accelerating at a constant rate of 5 ft/sec^2. It travels 100 ft while its speed changes to 60 ft/s. What is the initial velocity in ft/s?
Expand Hint
$$$v^2=v_0^2+2a_0(s-s_0)$$$
where
$$v$$
is the velocity along the direction of travel,
$$v_0$$
is the velocity at time
$$t_0$$
,
$$a_0$$
is constant acceleration,
$$s$$
is the displacement at time
$$t$$
along the line of travel, and
$$s_0$$
is the displacement at time
$$t_0$$
.
Hint 2
Solve for
$$v_0$$
.
For constant acceleration, the equation for velocity as a function of position:
$$$v^2=v_0^2+2a_0(s-s_0)$$$
where
$$v$$
is the velocity along the direction of travel,
$$v_0$$
is the velocity at time
$$t_0$$
,
$$a_0$$
is constant acceleration,
$$s$$
is the displacement at time
$$t$$
along the line of travel, and
$$s_0$$
is the displacement at time
$$t_0$$
.
Solving for initial velocity:
$$$(60ft/s)^2=v_0^2+2(5\frac{ft}{s^2})(100ft)$$$
$$$3,600ft^2/s^2=v_0^2+1,000ft^2/s^2$$$
$$$v_0=\sqrt{(3,600ft^2/s^2-1,000ft^2/s^2)}=\sqrt{2,600ft^2/s^2}=51\:ft/s$$$
51 ft/s
Time Analysis
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