Projectile Motion
Consider a spectator at a hockey game hurls a projectile towards the ice rink at an angle of 67° to the horizontal. If the object leaves the spectator’s hand at 5 m/s, what is the horizontal velocity in m/s?
Expand Hint
Hint 2
$$$v_x=v_0cos(\theta )$$$
where
$$v_x$$
is the horizontal velocity,
$$v_0$$
is the initial velocity, and
$$\theta$$
is the angle.
Because the object is thrown, the projectile has constant acceleration. Thus,
$$$v_x=v_0cos(\theta )$$$
where
$$v_x$$
is the horizontal velocity,
$$v_0$$
is the initial velocity, and
$$\theta$$
is the angle.
$$$v_x=(5\frac{m}{s})cos(67^{\circ})=(5\frac{m}{s})(0.391)=1.95\:m/s$$$
1.95 m/s
Time Analysis
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