Hoop Stress
If a thin-walled cylinder pressure vessel in the figure below has an inner radius of 0.25”, what is the tangential (hoop) stress?
Expand Hint
Tangential (hoop) stress of a thin-walled cylinder:
$$$\sigma_t=\frac{P_ir}{t} $$$
where
$$P_i$$
is the internal pressure,
$$r$$
is the average radius, and
$$t$$
is the wall thickness.
Hint 2
$$$r=\frac{r_i+r_o}{2}$$$
where
$$r_i$$
is the inner radius, and
$$r_o$$
is the outer radius.
Remember, a cylinder can be considered thin-walled if the wall thickness is about 1/10 or less of the inside radius. If so, the internal pressure is resisted by both the axial and hoop stress.
Tangential (hoop) stress of a thin-walled cylinder:
$$$\sigma_t=\frac{P_ir}{t} $$$
where
$$P_i$$
is the internal pressure,
$$r$$
is the average radius, and
$$t$$
is the wall thickness. To find
$$r$$
:
$$$r=\frac{r_i+r_o}{2}$$$
where
$$r_i$$
is the inner radius, and
$$r_o$$
is the outer radius. Thus,
$$$r=\frac{0.25inch+(0.25inch+0.03inch)}{2}=\frac{0.53inch}{2}=0.265\:inch$$$
Therefore,
$$$\sigma_t=\frac{500\frac{lb}{in^2}(0.265in)}{0.03in}=\frac{132.5}{0.03}psi=4,417\:psi$$$
4,417 psi
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