Golf Angle
Consider a golfer uses a 60° angled club to hit a golf ball in the sand bunker from rest. If the ball leaves the club’s face at 50 m/s, how far does it travel in the horizontal direction (m) after 3 seconds?
Expand Hint
Hint 2
$$$x=v_0cos(\theta)t+x_0$$$
where
$$x$$
is the horizontal distance,
$$v_0$$
is the initial velocity,
$$t$$
is the time,
$$x_0$$
is the initial starting distance in the horizontal direction, and
$$\theta$$
is the angle.
Because the object is smacked, the projectile has constant acceleration. Thus,
$$$x=v_0cos(\theta)t+x_0$$$
where
$$x$$
is the horizontal distance traveled,
$$v_0$$
is the initial velocity,
$$t$$
is the time,
$$x_0$$
is the initial starting distance in the horizontal direction, and
$$\theta$$
is the angle.
$$$x=(50\frac{m}{sec})cos(60^{\circ})(3sec)+0m$$$
$$$x=(150m)(0.5)=75\:m$$$
75 m
Time Analysis
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