Golf Angle

Consider a golfer uses a 60° angled club to hit a golf ball in the sand bunker from rest. If the ball leaves the club’s face at 50 m/s, how far does it travel in the horizontal direction (m) after 3 seconds?

Expand Hint
Hint 2
$$$x=v_0cos(\theta)t+x_0$$$
where $$x$$ is the horizontal distance, $$v_0$$ is the initial velocity, $$t$$ is the time, $$x_0$$ is the initial starting distance in the horizontal direction, and $$\theta$$ is the angle.
Because the object is smacked, the projectile has constant acceleration. Thus,
$$$x=v_0cos(\theta)t+x_0$$$
where $$x$$ is the horizontal distance traveled, $$v_0$$ is the initial velocity, $$t$$ is the time, $$x_0$$ is the initial starting distance in the horizontal direction, and $$\theta$$ is the angle.
$$$x=(50\frac{m}{sec})cos(60^{\circ})(3sec)+0m$$$
$$$x=(150m)(0.5)=75\:m$$$
75 m
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