Hockey Puck
Trying to score a goal, a hockey player hits a puck with a 100 N force, resulting in a horizontal velocity of 15 m/s. If the puck left the stick at 20 m/s, what angle (degrees) above the horizontal did the player hit the puck?
Expand Hint
Hint 2
$$$v_x=v_0cos(\theta )$$$
where
$$v_x$$
is the horizontal velocity,
$$v_0$$
is the initial velocity, and
$$\theta$$
is the angle.
Because the puck is smacked, the projectile has constant acceleration. Thus,
$$$v_x=v_0cos(\theta )$$$
where
$$v_x$$
is the horizontal velocity,
$$v_0$$
is the initial velocity, and
$$\theta$$
is the angle.
$$$15m/s=(20m/s)cos(\theta )$$$
$$$cos(\theta)=\frac{15m/s}{20m/s}=0.75$$$
$$$\theta=cos^{-1}(0.75)=41.4^{\circ}$$$
41.4°
Time Analysis
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