Cosines

For the triangle figure, what is the unknown angle in degrees?

Hint
Law of Cosines:
$$$b^2=a^2+c^2-2ac\:cos\:B$$$
Hint 2
For oblique (non-right) triangles, use the Law of Cosines to determine unknown sides/angles:
$$$a^2=b^2+c^2-2bc\:cos\:A$$$
$$$b^2=a^2+c^2-2ac\:cos\:B$$$
$$$c^2=a^2+b^2-2ab\:cos\:C$$$
Thus, to find angle $$B$$ :
$$$b^2=a^2+c^2-2ac\:cos\:B$$$
$$$2(15)(25)\:cos\:B=(15)^2+(25)^2-(16)^2$$$
$$$(750)\:cos\:B=225+625-256=594$$$
$$$cos\:B=\frac{594}{750}\Rightarrow B=cos^{-1}(\frac{594}{750})$$$
$$$B=cos^{-1}(0.792)=37.6^{\circ}$$$
37.6°