Sin
For the triangle figure shown, what is the unknown angle in degrees?
Expand Hint
Law of Sines:
$$$\frac{a}{sin\:A}=\frac{b}{sin\:B}=\frac{c}{sin\:C}$$$
Hint 2
For oblique (non-right) triangles, use the Law of Sines to determine unknown sides/angles:
$$$\frac{a}{sin\:A}=\frac{b}{sin\:B}=\frac{c}{sin\:C}$$$
Thus, to find angle
$$A$$
with the given knowns:
$$$\frac{a}{sin\:A}=\frac{b}{sin\:B}$$$
$$$\frac{16}{sin\:A}=\frac{22}{sin\:22^{\circ}}$$$
$$$sin\:A=\frac{16\cdot sin\:22^{\circ}}{22}=0.2724$$$
$$$A=sin^{-1}(0.2724)=15.8^{\circ}$$$
15.8°
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